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Mathematics 7 Online
OpenStudy (anonymous):

What is the area?

OpenStudy (anonymous):

area of what?

OpenStudy (anonymous):

OpenStudy (sasogeek):

half the base times the perpendicular height... you have everything you need :) plug in values and solve :)

OpenStudy (anonymous):

? bit confused

OpenStudy (anonymous):

:)

OpenStudy (diyadiya):

\[\huge \mathsf {Area = \frac{1}{2} \times base \times height }\]

OpenStudy (anonymous):

to calculate different type of area.. it used different equation.so which area do you want to calculate?

OpenStudy (anonymous):

this is rather complicated :) I don't understand anything

OpenStudy (diyadiya):

\[\mathsf { Area =\frac{1}{2} \times 7.9 \times 4.9 }\]

OpenStudy (anonymous):

diyadiya had answered your question. :D

OpenStudy (anonymous):

38.71

OpenStudy (diyadiya):

Now all you need to do is Multiplication & division

OpenStudy (anonymous):

19.355 m^2

OpenStudy (anonymous):

OK I am really confused..In turmoil :)

OpenStudy (anonymous):

7.9 times 4.9 = 38.71

OpenStudy (anonymous):

do u get it?

OpenStudy (anonymous):

calissa830..the area of triangle should be divide by two.you're calculating the area of square just now.

OpenStudy (anonymous):

wats ur answer?

OpenStudy (diyadiya):

@mathq The given triangle is a right triangle Base length = 7.9m Height = 4.9m \[Area of a \triangle = \frac{1}{2} \times base \times height\]\[Area =\frac{1}{2} \times 7.9 \times 4.9 \]\[= \frac{38.71}{2}=19.355m^2\]

OpenStudy (anonymous):

my answer is same as diyadiya.

OpenStudy (anonymous):

soory... ur right im doin my othe hw

OpenStudy (amistre64):

\[\int _{7.9}^0\ \frac{4.9}{7.9}a\ da \] maybe

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