Question

Solve the equation giving your answer correct to 3 significant figures.
ln(1 + x2) = 1 + 2 ln x

Answer 1

\[\ln(1 + x^2) = 1 + 2 \ln x\]

Answer 2

Numerical analysis a good way ... do you know Newton Raphson?

Answer 3

Well \( \large x = \frac{1}{\sqrt{-1+e}} \)

Answer 4

\[\large{e^{\ln(1+x^2)}}=e^{1+2lnx}\]\[\large{1+x^2=e^1e^{2lnx}}\]\[\large{1+x^2=e^1e^{lnx^2}}\]\[\large{1+x^2=e^1x^2}\]\[x^2(e^1-1)=1\]\[x^2=\frac{1}{e^1-1}\]

Answer 5

Um.. not following

Answer 6

um.. where are you struck?

Answer 7

I'm stuck on... well... everything?

Answer 8

Did you read lala's answer? She explained it quite well.

Answer 9

Yes, I see it... but can you explain it a bit slower? I'm not very good with the In equations...

Answer 10

Do you know \( \Huge a^{ \log_a b } = b \)

Answer 11

Now I do. :)

Answer 12

that's great, now you can figure out the rest ?

Answer 13

I'd still like some help if you would?

Answer 14

Btw the final answer is \( 0.763 \)

Answer 15

hm sure :)

Answer 16

Yup, the answer is here... but I just don't know how to arrive at it...

Answer 17

where are you stuck again?

Answer 18

the last two parts of lalaly's steps.

Answer 19

Actually, I understand that

Answer 20

How do you get the answer?

Answer 21

I used Mathematica

Answer 22

Thanks. I got it.

Answer 23

Glad to help :)

Answer 24

These videos might be too boring
http://www.khanacademy.org/?video=introduction-to-logarithm-properties#logarithms

but they are helpful if you need review, or have someone walk through the properties of logs

Answer 25

I'll check it out when I have time! :)