Question

if g(u)=(1)/(9u+6(1/2))

find g'(u)

Answer 1

do i flip it first?

Answer 2

\[g(u)=(9u+3)^{-1}\]

Answer 3

why 3?

Answer 4

is this 6 multiplied by 1/2?

Answer 5

the 1/2 meant that everything in the denominator is under a radical

Answer 6

ohh\[g(u)=\frac{1}{(9u+6)^{\frac{1}{2}}}\]?

Answer 7

yeah...

Answer 8

\[g(u)=(9u+6)^{-\frac{1}{2}}\]

Answer 9

do u know how to differentiate this?

Answer 10

multiply the first # by the power and reduce the power by 1

Answer 11

\[g'(u)=-\frac{1}{2}(9u+6)^{-\frac{3}{2}}\times 9\]

Answer 12

yeah then multiply it all by the derivative of whats inside the bracket

Answer 13

lalaly knows it all :D

Answer 14

wheres the 9 from?

Answer 15

got it?

Answer 16

lol fool no i dont

Answer 17

Chain Rule

Answer 18

yesss you doo! :D

Answer 19

haha

Answer 20

could someone explain the chain rule then? lol

Answer 21

http://tutorial.math.lamar.edu/Classes/CalcI/ChainRule.aspx