how are exponents related to taking the root of a number?
Depending on how you look at it, they're the opposite.
taking the square root of a number is the inverse of squaring the number
the root of a number can be represent by raising a number to a fractional exponent
So, for example, if I raise a to the 8th power, \(a^8\), then I can get \(a\) back by taking the 8th root of the result: \(\sqrt[8]{a^8} = a\).
As Dockworker points out, another way to look at it is that a root is actually just another kind of exponent—a fractional one. So \(\sqrt[8]{a} = a^{\frac{1}{8}}\).
okay i understand now thank u very much
If we look at it this way, \(\sqrt[8]{a^8} = (a^8)^{\frac{1}{8}} = a^{\frac{8}{8}} = a^1 = a\).
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Aw thanks :)
haa anytime
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