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At x =π, an equation of the line tangent to the graph of fx=cos1/2x is
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y = f'(pi)x -f'(pi)pi+f(pi)
what is the answer then
what is f'(x) ?
f'x is 0
no
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the derivative of cos(1/2 x) is not 0 :)
if this is base on a Essay then copy what @amistre said or if this is a choice question try to find the answer the match in his/hers answer. :)
-1/2 sin 1/2x
right; and when we pi into that we get: -1/2 sin(90) = -1/2 i beleive for our slope
y = -1/2 x + (1/2)*pi + f(pi) what is cos(pi/2)?
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y=1/2x + -1/2pi
thats seems right to me; or to clean it up \[y=-\frac{1}{2}+\frac{pi}{2}\]
\[y=-\frac{1}{2}x+\frac{pi}{2}\]
thanks amistre64
youre welcome :) good luck
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