Question attached!
i keep gettin this wrong!
y' = - 8x^3 + 3x^2 + 2x Alternate forms at the link: http://www.wolframalpha.com/input/?i=derivative+of+y+%3D+%282x%5E2+%2B+x%29%28x+-+x%5E2%29
Let me check. You're doing the first times deriv of the second and second times deriv of first -- factored form.
(x - x^2) (4x +1) + (2x^2 + x) (1 - 2x) Look at that and see if If did the product rule correctly.
Are you supposed to leave the answer in simplifed factored form? x can be factored from (x - x^2) and so on.
heres a example
ah wait wrong problem
I'm mixed up on what the red x and the zero out front mean.
Is this the original question ABOVE your work. I don't know how to read this input form. screenshot20120221at5.33.51pm.png
Hey, I called for some help over here. Hold on.
THANK YOU!
Here's what my method would be: Use FOIL to find \((2x^2+x)(x-x^2) = -2x^4+x^3+x^2\) Then finding the derivative of that should be very straight forward.
Namely, the derivative should be \(-8x^3 +3x^2+2x\)
nevermind, I was doing the first problem, but the method should be the same for the second one you posted.
\((4x^2 +x)(x-x^2)=-4x^4 +3x^3+x^2 \) So the derivative should be \(-16x^3+9x^2+2x\)
I think the issue is trying to figure out what the answer program will accept.
Have you tried inputting simply \(-16x^3+9x^2+2x\) or something of a similar form?
nope i think they want a (...)(...)+(...)(...) type of answer
In that case, \[{dy \over dx} (4x^2+x)(x-x^2) = (8x+1)(x-x^2)+(4x^2+x)(1-2x)\]By the rule for deriving multiplications. However, it would appear you've already tried that. Are you sure they want a (...)(...)+(...)(...) type of answer?
that one was the example problem the real one is at the top!:(
My apologies, the derivative of the one at the top is\[{dy \over dx} (2x^2+x)(x-x^2) = (4x+1)(x-x^2)+(2x^2+x)(1-2x) = -8x^3+3x^2+2x\]
Did this help? Or is it still giving you strange error messages?
still wrong but im gonna move on from it might be an instructor error thank you for the help!
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