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8^(6+3x)=4
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\[2^{3(6+3x)}=2^2\]
set exponents equal to each other
and then what? I need to solve the equation
right!
after you have the exponents equal you distribute the 3 to (stuff)
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\[18+9x=2\]
8^(6+3x)=4 So now divide by 4 2^(6+3x)=1 Then take logs of both sides, if i remember correctly.
\[9x=2-18 => 9x=-16 => x=-\frac{16}{9}\]
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