Find the area of the following figure. The base angles are right angles. (Drawing the picture)
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There's a rectangle and a triangle there. Add up the areas of the 2 figures.
The height of the triangle is 4. Its base is the same as the width of the rectangle, 11.
not to be picky, but the figure is impossible. It would be possible if the altitude of the triangle were 4.33
I was referring to the lengths, and the requirement that the base angles are 90 degrees
I was studying from the book & I didnt understand it so I asked for help :c The answer was in the back of the book but I wanted to see how to do it..
Did the book give the lengths of 9 for the sides, 11 for the bottom, 7 for the two sides up top, and 4 for the altitude?
Yes o.o
I put the lengths exactly like the book says.
Then it is a bad example. But we can pretend it is real....
I'm sorry =[
You didn't write the book. The area of the rectangle part is 11*9= 99 (area= width times height)
the area at the top is the area of a triangle. Area of a triangle is 1/2 base*height the base is 11 (we know this because the 11 is the width of the rectangle). the height is 4 so 1/2 * 11 * 4= 22 together, rectangle + triangle = 99+22= 121
Ohh $:
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