Assume that the box contains 2 defective widgets and18 acceptable widgets. There are 5 inspectors, each of whom selects a widget from the box at random, inspects it, and then replaces it in the box. Each inspector makes his or her inspection at a different time.
What is the probability that at least one inspector will find a defective
widget?

Question

Assume that the box contains 2 defective widgets and18 acceptable widgets.  There are 5 inspectors, each of whom selects a widget from the box at random, inspects it, and then replaces it in the box.  Each inspector makes his or her inspection at a different time.
What is the probability that at least one inspector will find a defective
widget?

anonymous · Answer

easier to compute the probability that no inspector finds a defective one
that should be straightforward

anonymous · Answer

thats what I thought but my setup is probably not right

anonymous · Answer

This is my FINAL bernoulli trial problem thank goodness

anonymous · Answer

probability that any one inspector finds a defective one is 
$$\frac{1}{9}$$ and doesn't find one is 
$$\frac{8}{9}$$ so it should be 
$$1-(\frac{8}{9})^5$$ i think

anonymous · Answer

"at least one" is a set up for "not none"

anonymous · Answer

cant get it to work