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NaOH+HCL->NaCl+H2O If 10.0g NaOH are reacted with the stoichiometric amount HCL, how many moles of NaCl should be isolated? What would this weigh?
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Moles of NaOH=10/40=0.25 Moles of NaCl=moles of NaOH=0.25 Weight=0.25*58.5=14.625
Thank you! I was halfway there and didn't even realize it.
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