how do i evaluate

1 ) the integral of 3^X dx

2)the integral from -2 to 0 of (3^3-5^2)

Question

how do i evaluate 

1 ) the integral of 3^X dx

2)the integral from -2 to  0 of (3^3-5^2)

mimi_x3 · Answer

$$\large \int\limits3^{x}  dx $$

mimi_x3 · Answer

You have to like change the base so...
$$\large e^{\ln3*x}  $$

anonymous · Answer

oh i c , i really need a good website that has all different types of problems our book is horrible

mimi_x3 · Answer

wait..i made a typo..
$$\large \frac{1}{\ln3}  *3^x + C=>\frac{3^{x}}{\ln3}   +C$$

anonymous · Answer

im in calc how do you remember and know which formats to use?

mimi_x3 · Answer

Hm..I used the formula..
change of the base.
$$\large a ^{bx + c} = e ^{lna*(bx+c)}$$
Primitive:
$$\large \frac{1}{blna}  *a^{bx+c}  $$
It's kinda confusing..probably you have a better one. xD

anonymous · Answer

ya this is the one our book has thanks i just have trouble ordering it when they get complicated

mimi_x3 · Answer

ordering it..?

anonymous · Answer

do you know a website that has this info in simple  explenations?
 i dont get the book descriptions at all

anonymous · Answer

i can copy similar problems but i dont rlly get what its meaning so i can work more complex ones

mimi_x3 · Answer

No sorry; those formulas are from my book.
What don't you get?

anonymous · Answer

how would u go about the second example?

mimi_x3 · Answer

I have to go now; sorry. Try posting it again, someone might be able to help you.

anonymous · Answer

alright thanks