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Find the area of the sector formed by central angle (theta) = 3pi/5 in a circle of radius r=4m.
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\[\underline{\text{area of sector}}=\frac{1}{2}r^2 \theta\]\[=\frac{1}{2}(4m)(\frac{3}{5}\pi)\]
So, would I be left with 2m (3/5pi)? Then, left with 6pi/5?
the m is meters? or just a variable?
It's meters.
oh then yeah u got it:)
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Well, when I put it in the calculator, it came out to be 3.77. That answer is wrong somehow. :/
why wrong? ..do u have the right answer?
I'm pretty sure I did it right, by the formula you gave me. That is a correct formula.
ohhhh i did something wrong lol
forgot to square the radius\[A=\frac{1}{2}(4)^2(\frac{3}{5}\pi)\]
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Im sorry -_-'
Oh!!! No, it's fine!
Now you'll get it right:)
Mhm!!! :D
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Got it! :) Thank you!!
:)
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