Question

log6(x+3)+log6(x+4)=1

Answer 1

\[\log_{6}(x+3)(x+4)=1 \]
\[6^1=((x+3)(x+4)\]
\[x^2+7x+12=6\]
\[x^2+7x+6=0\]

\[(x+6)(x+1)=0\]
\[x=-6, -1\]

Answer 2

But -6 causes a negative argument so discard it and the result is x = -1