Question

What is the sum of a 6–term geometric series if the first term is 7 and the last term is 229,376?

Answer 1

good lord

Answer 2

Yeah :/

Answer 3

ok we can do it

Answer 4

7 + 7r+7r^2+7r^3+7r^4+7r^5\] is what you are looking for, and you know that
\[7r^5=229,376\] so
\[r^5=\frac{229376}{7}=32768\] and so
\[r=\sqrt[5]{32768}=8\]

Answer 5

so we can add them directly or by the formula
\[a+ar+ar^2+ar^3+ar^4+ar^5=a(1+r+r^2+r^3+r^4+r^5)=a\frac{r^6-1}{r-1}\]

Answer 6

\[a\frac{r^6-1}{r-1}\]

Answer 7

should get
\[\frac{7(8^6-1)}{8-1}=8^6-1=262143\] maybe i made a mistake.

Answer 8

No I think thats right wow thank you so much satellite :)

Answer 9

yw

Answer 10

YOU are the best :)

Answer 11

lol

Answer 12

I'm serious lol :)