Okay, so im factoring these trinomials right? no biggy, but then i realized, im stuck... heres what i have so far (5x^2+10x)(-3x-6) then that goes to .... 5x(x+2)...... but the next one would it be a negative # or positive # on the outside??????

Question

Okay, so im factoring these trinomials right? no biggy, but then i realized, im stuck... heres what i have so far     (5x^2+10x)(-3x-6)    then that goes to ....         5x(x+2)...... but the next one would it be a negative # or positive # on the outside??????

anikate · Answer

ok I can do this

anikate · Answer

wait sry it's trynomials

anikate · Answer

nevr hurd of it

anonymous · Answer

if it helps, the original problem is 5x^2+7x-6

anonymous · Answer

well, the instructions say to factor the trinomials, i used the formula ax^2+bx+c

paxpolaris · Answer

$$5x^2+7x-6$$$$=5x^2+10x\ \ -3x-6$$

anonymous · Answer

yeah....

istim · Answer

That should help get you started.

istim · Answer

You should be able to work on from here.

paxpolaris · Answer

$$=5x(x+2)-3(x+2)$$

anonymous · Answer

i already have that, then i grouped them and i dont know if the second section should have the coefficiant thing be negative or positive...

paxpolaris · Answer

$$\Large=(5x-3)(x+2)$$

anonymous · Answer

okay.... im a little confused on how exactly the numbers are distibuted to the outside...

paxpolaris · Answer

take first to terms and factor the common out... then the last two

anonymous · Answer

okay, and what if it has a variabe with an exponent?

istim · Answer

What?

anonymous · Answer

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