Question

6 men and 8 women are going to be assigned to a specific row of seats in a theater. If the 14 tickets for the numbered seats are given out at random, find the probability that exactly one womb is in one of the first 5 seats.

Answer 1

woman not womb hahahahah

Answer 2

no same thing

Answer 3

what?

Answer 4

lololol XD

Answer 5

does anyone know how to do this?

Answer 6

This should be equivalent a number of combinations of n objects taken r at a time.
Remember nCr = n! / [ (n - r)!r!
a) There are 14C5 ways to select 5 people (to fill the first five seats) out of a total of 14 people (men and women). 14C5 =14!/[14-5]!5! =2002
b) There are 8C1 ways to select 1 woman out of 8. =8!/[8-1]!1!
c) There are 6C4 ways to select 4 men out of 6 = 6!/[6-4]!4!
d) There are 8C1*6C4 ways to select 1 woman out of 8 AND 4 men out of 6.
8C1*6C4= 120 ( from c and b above)
Probability of choosing 1 woman and 4 men = P( 1 woman 4 Men)
P(1 woman 4 Men) = 8C1*6C4/ 14C5 = 120/2002 =0.059940
Please verify accuracy of arithmetic.

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