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Find the derivatives using the table (I will post the table) a. Dx(f[g(x)]) at x=1 b. same at x=2
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x 1 2 3 4 f(x) 2 4 1 3 f'(x) -6 -7 -8 -9 g(x) 2 3 4 1 g'(x) 2/7 3/7 4/7 5/7
∫ f ′(x) f (x) dx = ln ( f (x)) + C
(f[g(x)])' = f '(g(x)) * g' (x), at x = 1 f ' (g(1)) * g'(1) = f ' (2) * (2/7) = -7 * 2/7 = -2
that was the answer to the first one.
thats for A
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awesome, thats what I got for the first one- not doing integrals yet so i cant use madiners
for the second one: f ' (g(2)) * g'(2) = f ' (3) * 3/7 = -8*3/7 = -24/7
for B x ln(x)d
lol thanks bahrom...no idea what is going on in your answer madiner but thanks for the input
thnk bahrom i didnt know that he didnt learn intergrels
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