Suppose that a culture of bacteria has an initial population of n=100. If the population doubles every three days, determine the number of bacteria present after 30 days. How much time is required to reach 4250 in number?

Question

anonymous · Answer

uhm can you explain using the malthus method i guess

.sam. · Answer

Is the answer correct?

.sam. · Answer

Do you have the answer?

anonymous · Answer

it says 16.23 days

.sam. · Answer

Geometric progression

.sam. · Answer

First term is,
$$a _{1} = 100$$
After 3 days, which is the fourth term,
Use formula
$$a _{n}=a _{1}r ^{n-1}$$
$$a_{4}=100r ^{3} =200$$
r=1.2599

.sam. · Answer

n= days,

When n days, (use back the formula)
$$a _{n}=100(1.2599)^{n-1}=4250$$

.sam. · Answer

n= 17.22

.sam. · Answer

Use natural logarithm to solve.

anonymous · Answer

okie dokie...i dont know if this helps but in differential equations i'm suppose to use like this half life equation y=e^kt+c