Determine whether the given description is of a one-to-one function: f(t) is the height of a football t seconds after kickoff. The answer is no but idk why.
Since the football goes up and then down, it reaches some height twice. Once while it's moving upwards, and once while it's moving downward. Thus, since it has the same y-value for two x-values, it isn't one-to-one.
But f(t) is at t seconds after kickoff. Based on your answer (I'm thinking of a concave down parabola), f(t) has reached it's maximum point and is returning to the height of however high a football is. Let's assume f(t) is 4-(t-2)^2. Are you saying that t hits both points just above the x-axis (the x-axis being the ground) because the question is asking about kickoff.
In your example, take when t=1, and when t=3. In both cases, f(t)=3. Since both values for t give the same value for f(t), it isn't one-to-one.
So basically, the value of t is indefinite and since there was no restriction, t can be both 1 and 3. Is that what you're saying?
Basically. In formal math terms, since \(f(t_1) = f(t_2)\) does not imply \(t_1 = t_2\) it isn't one-to-one.
Okay, thanks. I actually chose that example since t=0 as the starting point is more realistic. After all, time can't be negative. Other than that, thanks for the explanation.
You're welcome.
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