Question

Determine the domain, range, and horizontal asymptote of f(x)=(3/4)^(x+3)

Answer 1

the asymptote is y = 0.... as x gets extremely large (3/4)^(x+3) gets close to zero....

so the domain is all real x.... same as any exponential function

range is y> 0

Answer 2

Domain: set of Reals
Range: y > 0

Horizontal Asymptote: y = 0

Answer 3

How is it I go in and find the real #s....would it be 3/4

Answer 4

I need to know how to work all of it out

Answer 5

since there is no denominator, domain is always real #
if there is a denominator then be careful those values which makes denominator to zero..

Answer 6

I dont know how to put any of it into an equation or whatever to know what is what, meaning real #s

Answer 7

for example
x^2/(x-2)
domain all real # except 2

Answer 8

so in this equation my real #s would be 3/4 and 3

Answer 9

N={0,1,2,...... }naturel #s
Z={.......-1,0.1,2,....} integers
Q=a/b a and b Z
R=Q+ Irrational #
i.e
Q= 1/2, -3/23, 2 , 0 24/1000
I=sqrt3, Pi, 1/2+srtq8
R={.....-1000.....-2,-1,0,1/2,3/2,sqrt 28.......}

Answer 10

\[R=(-\infty, \infty)\]

Answer 11

real #s any numbers except complex numbers..