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OpenStudy (anonymous):
or 1 over 2 plus 1 over 3 equals 1 over x
OpenStudy (anonymous):
First step is to combine the 1/2 and 1/3.
OpenStudy (anonymous):
how would u do that
OpenStudy (anonymous):
You need to make sure they have the denominator.
OpenStudy (anonymous):
wuld it be 6
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
so what next
OpenStudy (anonymous):
Do you have one fraction on the left?
OpenStudy (anonymous):
no im completely lost
OpenStudy (anonymous):
ok, well we can combine fractions if they have the same denominator.
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OpenStudy (anonymous):
But that's not the case right now: we have 1/2+1/3
OpenStudy (anonymous):
So we're going to get them both the same denominator: 6, as you said.
OpenStudy (anonymous):
Like this: \[\frac{1}{2}=\frac{3}{6}\]
OpenStudy (anonymous):
Now can you do \[\frac{1}{3}=?\]
in a similar way?
OpenStudy (anonymous):
2 over 6
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OpenStudy (anonymous):
right so we get:
\[\frac{3}{6}+\frac{2}{6}=\frac{1}{x}\]
OpenStudy (anonymous):
So what's the next step?
OpenStudy (anonymous):
no clue
OpenStudy (anonymous):
this is the problem if it helps 1. It takes Matt 2 hours to work out and it takes his friend Evan 3 hours to work out. How long would it take Matt and Evan to work out together? and then you have to turn it into a rational equation
OpenStudy (anonymous):
I don't understand that question, but I can solve the equation for x.
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
So if you're sure you have the right equation we'll solve it.
OpenStudy (anonymous):
\[\frac{3}{6}+\frac{2}{6}=\frac{1}{x}\]
OpenStudy (anonymous):
yes thats correct
OpenStudy (anonymous):
Ok, you need to combine the two fractions on the left, just add them together.
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OpenStudy (anonymous):
5 over 6
OpenStudy (anonymous):
right
\[\frac{5}{6}=\frac{1}{x}\]
OpenStudy (anonymous):
so wat now
OpenStudy (anonymous):
When you have one fraction equals another fraction you can flip it over, as long as there are no zeroes anywhere, like this:
\[\frac{a}{b}=\frac{c}{d} -> \frac{b}{a}=\frac{d}{c}\]
OpenStudy (anonymous):
Can you apply that here?
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