Question

f(x)=e^sqrt(4x+4)

find f'(x).

the answer is 4e/2sqrt(4x+4), right?

Answer 1

2(4x+4)e^((4x+4)^1/2)

Answer 2

can you show me the steps u used then?

Answer 3

\[(e ^{\sqrt{4x+4}})' = e ^{\sqrt{4x+4}} * (\sqrt{4x+4})' * (4x+4)'\]

Answer 4

Bring down the exponent,

(4x+4)^1/2 e^(4x+4)^1/2

differentiate the exponent that you just bring down

2(4x+4)^3/2 e^(4x+4)^1/2

Answer 5

I noticed that there is a slight error in my post,
2(4x+4) should be 2(4x+4)^-1/2

Answer 6

but thats not the final answer Niker, is it?

Answer 7

http://www.ms.uky.edu/~ma123/

I dont know if you can view this, but example 3 is just like this problem...

Answer 8

\[2e ^{\sqrt{4x+4}} / \sqrt{4x+4}\]

Sorry, uh the first time I posted I put a 4x, when it should have been just 4

Answer 9

you have to click on lecture notes then on chapter 6 notes with answers

Answer 10

and then?

Answer 11

lecture notes
ch 6 notes w/ answers
example 3

Answer 12

Oh, you meant suplemntary

Answer 13

The answer you gave me is wrong by the way

Answer 14

Why is it wrong

Answer 15

o yeah, i did mean that.

Answer 16

my hw website said so

Answer 17

unless im putting it in wrong. its an old school site. you have to use parenthesis, ^, ^1/2, and etc...

Answer 18

Tell me if it works out =/

Answer 19

its not

Answer 20

http://www.wolframalpha.com/input/?i=derive+e^sqrt%284x%2B4%29
=/

Answer 21

any suggestions?

Answer 22

thats a whole different answer than what u gave me

Answer 23

Actually its not, they just factored out the fours and canceled out

Answer 24

this is what i put in my hw site:
(2*e)^(4x+4)^(1/2))/((4x+4)^(1/2))

Answer 25

(2*e)^ ( (4x+4)^(1/2)) / ((4x+4) ^(1/2))

Answer 26

I dont know

Answer 27

somethings wrong

Answer 28

and i did have 2 parenthesis before the 4x

Answer 29

((2*e)^ ( (4x+4)^(1/2)) )/ ((4x+4) ^(1/2))

Maybe add another one?

Answer 30

nope...

Answer 31

Does it want the super simplified form? >>
Sorry if im not any help at all

Answer 32

i think the answer is wrong because it doesnt say its a syntax error when i enter it

Answer 33

e^[ (4x+4)^0.5] = e^2(x+1)^0.5
f'(x) = e^2[(x+1^0.5] * (x+1)^(-0.5)
= e^2(x+1)^0.5 / (x+1)^(0.5)

Answer 34

thats not right either :(

Answer 35

ok i added some parenthesis and now its correct!!!

Answer 36

ok - where are the parantheses?

Answer 37

e^(2(x+1)^(1/2))/((x+1)^(1/2))

Answer 38

yes ok - putting those in avoids any possible ambiguity

Answer 39

i dont understand how u got 2(x+1) though

Answer 40

could u explain jimmy

Answer 41

Its the same thing as what i said, he just took out the 4..

Answer 42

do u mean on the first line?

Answer 43

yeah... e^2(x+1)^1/2

Answer 44

yea sqrt (4x+4) = sqrt4 * sqrt(x+ 1)
= 2(x+1)^(1/2)

Answer 45

i see...