Question

Solve by Completing the square.
b^(2)+2b+10=0

Answer 1

b= -1 plus or minus 3i

Answer 2

We know
\[(a+b)^2=a^2+2ab+b^2\]
here we have
\[b^2+2b+10=0\]
\[b^2+2b+1+9=0\]
\[(b+1)^2+9=0\]
or \[(b+1)^2=-9\]
we get
\[(b+1)=\pm 3i \]
\[( i =\sqrt{-1} )\]

we get
\[b=-1\pm3i\]

Answer 3

b^2+2b+10=0
b^2 + 1 = -10 +1
( b + 1)^2 = -9
-> b+1 = +/- sqrt ( -9) = +/-3i
=> b = -1 +/-3i