Determine whether the following are subspaces of P4(Polynomial). The set of all polynomial of degree 3
think you are missing the identity
?
ok sorry, what i guess i mean is you are missing the zero vector
one vector space axiom says there must be a 0, that is a vector \[\overrightarrow{0}\] with \[\overrightarrow{0}+\overrightarrow{v}=\overrightarrow{v}\]
if you have polynomials of degree three only, there is no zero vector
so in what cases would it have a zero vector?
you would need maybe all polynomials , so that would include the zero polynomial
or maybe all polynomials of degree 3 or less say, but it has to include zero
ok thanks
but if you fix the degree it wont work here is a simpler explanation, it has to be closed under vector addition so \[x^3+(-x^3)=0\] tells you it is not even closed
so "the set of alll polynomial p(x) in P4 such that p(0)=0" would be subspace since it has zero vector?
i am not sure what P4 is, but i believe yes, that would be a subspace. add them still works, subtract two all the other axioms work and it contains the zero polynomial for sure
you can check the axioms one by one (which is the point of this exercise) and see that they will all work
what do I add?
alpha (a x^4+ b x^3 + c x^2 +d x ) (a x^4+ b x^3 + c x^2 +d x )+ (e y^4+ f y^3+g y^2+h y)= ?
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