Question

f(x)=e^x+4lnx
find f'(6).

Answer 1

e^6 + 2/3

Answer 2

show work please

Answer 3

f'(x) = e^x + 4/x .

d(lnx)/dx = 1/x

so, f'(6) = e^6 + 2/3

Answer 4

im getting 785.77 but thats wrong

Answer 5

If I calculate the value of e^6 , it comes out to be approx 136.821.
Then add 1.333 to it.
Comes out to 138.154

Answer 6

why am i not getting these numbers?

Answer 7

you might be doing some silly mistake. Check again.

Answer 8

when i type in e^6 i get 403.43

Answer 9

in my calc

Answer 10

nobody knows what we're doing wrong?

Answer 11

\[e^6\approx403.4287\]according to my calculator

Answer 12

well then I guess I am wrong...I'll check again! :P

Answer 13

ditto

Answer 14

oh I thought your decimal was in a different spot sidd

Answer 15

but\[2.5^6=\frac{5^6}{2^6}=244.14...<e^6\]so mario's answer makes sense

Answer 16

Yea....but if you see the expansion of e^x which is equal to 1 + x/1! + x^2/2! + x^3/3!.....so on,
the value doesn't come out to be 403.287

Answer 17

im so lost...

Answer 18

Any way I look at it, I'm getting \(f'(6) = e^6 + {2 \over 3}\) Which is about 404.095

Answer 19

thats incorrect george...

Answer 20

Do you know what the answer is?

Answer 21

Oh and its showing 403.428 on the calculator but why doesn't the same value come when I use the expansion of e^x?

Answer 22

no. thats why im here.
are we setting this up right?

Answer 23

How do you know that's wrong then?

Answer 24

i put it in my hw website and it tells me if i got it right or not

Answer 25

Have you tried putting in the exact formula \(e^6 +{4 \over 6}\) ? Several of the websites I've used that have hw problems on them need it in the exact form, not decimal.

Answer 26

it says, find f'(6), correct to two decimal places on there

Answer 27

That's weird.

Answer 28

Well mario I think the answer is 404.75. So just go with this.

Answer 29

its not :C

Answer 30

this is getting frustrating

Answer 31

404.10? That's what I keep getting. If it's not that, I honestly have no idea what we're dong wrong.

Answer 32

its not

Answer 33

Ask your teacher. That's all I have left.

Answer 34

Input: f (x) = e^x + 4 log (x)

Answer 35

what is not going right?
\[f'(x)=e^x +\frac{4}{x}\]
\[f'(6)=e^6+\frac{2}{3}\]

Answer 36

Juss said that :) ^

Answer 37

404.09546015940178927505384721005494627256656402379586..

Answer 38

Is the answer 397.43?

Answer 39

no

Answer 40

@mariomintchev do u have choices that can help us to help you..

Answer 41

404.095.... rounds off to 404.10, right?

Answer 42

its not multiple choice

Answer 43

I don't know what the answer is then. Ask your teacher.

Answer 44

thats what i mean. it says to round to 2 decimal places

Answer 45

i gotta go for now but if u all come up with something, write it here.

Answer 46

two decimal place accuracy gives 404.10

Answer 47

http://www.wolframalpha.com/input/?i=e%5E6%2B4%2F6

Answer 48

e^6+4/6

Answer 49

ok. im back. ive tried everything but i have been unsuccessful. any ideas? i can give you my hw website login info if you wanna try for yourself.

Answer 50

it's not that hard of a problem
the answer to the problem as you posted it is
f'(6)=e^6+2/3
the possibilities are
1)your post has a typo
2)the website has a glitch

Answer 51

\[f(x)=e^x+4\ln x\]\[f'(x)=e^x+\frac4x\]\[f'(6)=e^6+\frac23\]now if the problem is not this, then it makes sense
otherwise that's all she wrote

Answer 52

everything is raised

Answer 53

not just the x

Answer 54

e^(x+4lnx)

Answer 55

Oh then the derivative is--

f'(x)=[ e^(x + 4lnx) ].[ 1 + 4/x]
f'(6)= [ e^(6 + 2/3)].[ 1+ 2/3]

No just calculate the value of that...