Question

integrate:

ʃ [e^-(1/2-t)x] / -(1/2-t)^2 dx

Answer 1

how is this very different that the one I already did for you?

Answer 2

\[u=-(\frac12-t)x\]\[du=-(\frac12-t)dx\]

Answer 3

its got a minus

Answer 4

do u know how to simplify this....

Answer 5

look, it's the same dang problem\[u=-(\frac12-t)x\]\[du=-(\frac12-t)dx\]\[dx=-\frac{du}{12-t}\]now make the substitution and see what happens to your integral