If f(x) = 4x + 1 and g(x) = 3x + 2, what is f(g(x)) ?
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OpenStudy (anonymous):
you put g in f's place like so
OpenStudy (anonymous):
f(g(x)) = 4(3x+2) +1
OpenStudy (anonymous):
12x+8 +1
OpenStudy (anonymous):
12x+ 9
OpenStudy (anonymous):
solve for zero:
12x = -9
x= -3/4
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OpenStudy (anonymous):
i get it thanks so much!
OpenStudy (anonymous):
No problem :)
OpenStudy (accessdenied):
i dont quite understand why you solve for the zero if it only asked for f(g(x))
OpenStudy (accessdenied):
it seems sufficient to just say
f(g(x)) = 12x + 9
OpenStudy (anonymous):
yepp, thats the answer. 12x+9
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OpenStudy (anonymous):
I was just being overly cautious ;)
OpenStudy (anonymous):
do you guys know how to do this one?
Let f(x) = 3x+1 and g(x) = x2
Find f(g(x))
then Find g(f(x))
and after Use complete sentences to explain any difference in part 1 and part 2.
OpenStudy (accessdenied):
x2 as in, x squared? it'd be the same process as the previous one
i use x^2 to indicate the exponent so theres no confusion
f(g(x)) = f(x^2) = 3(x^2) + 1
g(f(x)) = g(3x + 1) = (3x + 1)^2
im not very good with the worded explanation for this. i guess you'd write that the process is the same, the values you are applying it to varied