Part 1: Determine whether 2 is a zero of the polynomial P(x) = 3x3 – 6x2 – 3x – 18 by using the Remainder Theorem. Show your work. (4 points) Part 2: Explain how the Remainder Theorem is useful in finding the zeros of a polynomial function. (4 points)
i believe the remainder thrm says; if P(2) = 0, its a zero
which to me seems rather redundant. How to determine of a given value is a zero? plug it in and see if you get a zero ...
i've been using purple math to help me, but i just got stuck on this problem. can you teach it to me step by step please?
i can, but what method are you wanting to use?
synthetic or long hand?
synthetic please
synthetic requires that all the positions be accounted for; in other words; the coeffs of the x^n parts in descending order all have to be there. 3x3 – 6x2 – 3x – 18 3 2 1 0 this HAS all its parts so no zeros need to fill in; so strip it down to coeffs 3 -6 -3 -18 we good so far?
yepp!
good now we can proceed with the set up: start with an initial 0 in the add row and set up your "zero" in the multiply row 3 -6 -3 -18 0 <------ add this row ---------------- 2) <----- multiply this row this make sense?
yepp, good so far (:
i set it up this way as opposed to the confusing and self defeating format
lets start by adding our 3+0 take that result and multiply it by our 2, and stick that result into the add row 3 -6 -3 -18 0 3(2) <------ add this row ---------------- 2) 3 <----- multiply this row this process is repeated to the end
3 -6 -3 -18 0 6 0 -6 ---------------- 2) 3 0 -3 -24 <-- this last number is the value we get for P(2)
if that last value is a 0, then P(2) = 0 and 2 would have been a root
ohhhh i get it!!
thanks so much (:
good luck :)
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