Question

Determine the equation of the line tangent to

g(x)=2x^4+5/x-3 at x=-1

Write your answer in slope-intercept form (y = mx + b).

Answer 1

f'(x)= 8x^3+5x^-1

Answer 2

Sorry dont know how to explain

Answer 3

take the derivative
replace x by -1 to get your slope
replace x by -1 in origninal function to get the second coordinate of the point
use the point slope formula to find the equation

Answer 4

f'(x)=8x^3-5

Answer 5

not clear if this is
\[g(x)=2x^4+\frac{5}{x-3}\] or
\[g(x)=2x^4+\frac{5}{x}-3\] but i am guessing it is the first one

Answer 6

second one

Answer 7

ok then
\[g(-1)=2-5-3=-6\] so your point is (-1,-6)

Answer 8

and
\[g'(x)=8x^3-\frac{5}{x^2}\] therefore
\[g'(-1)=-8-5=-13\] so you have the point and the slope, should be good from there yes?

Answer 9

wait how did you get 8x^3-5/x^2?

Answer 10

and how do you solve for b?