How do I solve by factoring: 2y^2 + 5y = -2?
I got y^2 + 5/2y + 1 =0 now what?
you could use the quadratic formula but that is time consuming ...
here's how I solve it : 2y^+5y+2 =0
I have to use factoring..
Take a and c and multiply them : 2*2 = 4
so I don't divide by 2 to get y^2?
b is the sum ... look for factors of 4 positive and negative that add up to 5...
you don't have to ...
factors of 4 adding up to 5 are 4 and 1 ...right?
Now... substitute b with the two terms we found (4 and 1 )
2y^2 +4y +1y +2 =0 same thing right?
now factor by grouping ...can you do that?
2y(y+2)+1(y+2) =0 and factor the GCF -> (y+2)(2y+1)=0
yeah I can thank you!
You're welcome ...this method works for all trinomials with leading coefficient ≠1
btw you have to divide by 2 when you have to solve by Completing the Square .
factor the GCF -> (y+2)(2y+1)=0? What do you mean?
ohh, okay.
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