integral of (3x+7)/x^2

Question

anonymous · Answer

could u show me the steps. i tried using u=x^2 is that right

anonymous · Answer

no

anonymous · Answer

easier to divide each term by x^2 and do it piece by piece

anonymous · Answer

thats hat i thought

anonymous · Answer

$$\int\frac{3}{x}dx+\int\frac{7}{x^2}dx$$ etc

anonymous · Answer

thanks so much lemme do it and then we could compare answers

anonymous · Answer

Yes, actually, you can do it via u substitution. Set u=3x+7, x=(u-7)/3. Which is ugly.

anonymous · Answer

i'll stick to the first suggestion

anonymous · Answer

this is my first time on this site...its pretty awesome

anonymous · Answer

anonymous · Answer

should get the answer easily now yes?

anonymous · Answer

just to check your answer ... you can click the button "Show steps"

anonymous · Answer

@mathg8 i tried wolfram but their process is way too long

anonymous · Answer

even without wolfram i bet you can do it in your head.
first part gives 
$$3\ln(x)$$ second give 
$$-\frac{7}{x}$$

anonymous · Answer

true ...they're using u substitution ...

anonymous · Answer

satellite 73 method ...best !

anonymous · Answer

Int (3x+7)/x^2
= 3 Int ( dx/x) + 7 Int ( dx/x^2)
= 3lnx - 7/x + C

anonymous · Answer

yeah thats what i got

anonymous · Answer

Do you have any other questions?

anonymous · Answer

im going through my review for my test tomorrow. if i run into any difficulties i'll let u know

anonymous · Answer

I'm glad you get the right answer :)

anonymous · Answer

integral of (ln(ln(x))/(xln(x))

anonymous · Answer

Let u = lnx -> du = dx/x
-> int ( Ln u du/ u )
Again let t = Lnu -> dt = du/u
-> Int ( tdt) = t^2/2 =  (Lnu)^2/2 = Ln (lnx)^2/ 2 + C

anonymous · Answer

why are you using a "t" variable