Question

f(x)= sin^2x i get using the product rule, but I get stuck after 2sinx cosx

Answer 1

what are you trying to do?

Answer 2

\[f(x) = (sinx)^2\]
\[f'(x) = 2(sinx)*(cosx)\]
So the trig identity is:
\[\sin2x= 2sinxcosx\]

Answer 3

also (sinx)^2 = 1/2*(1-cos2x)

Answer 4

Yeah, but that is hard to differentiate i guess..

Answer 5

not really

Answer 6

you don't have to use product rule

Answer 7

just the chain for cos(2x)

Answer 8

I didn't use the product rule for that, i think i used the chain rule..

Answer 9

I understand that. I know what the chain rule is he hasnt taught it to us yet. the example demonstrated the product rule.

Answer 10

remember the formula above for when you're going to integrate sin^2(x)

Answer 11

@math: um, this is differentiate, i think you got kind of confused

Answer 12

not really

Answer 13

how would i solve this using only the product rule?

Answer 14

(sinx)^2 = 1-cosx*cosx

Answer 15

now you can use the product rule