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Calculate the indefinite integral of: sec(x) dx I would like a hint please.
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Write \[ \sec x = \frac{\sec x (\sec x + \tan x)}{\sec x + \tan x } \]
How did you get the above expression?
just multiply by\[\frac{\sec x+\tan x}{\sec x+\tan x}\]it's not an obvious move at first, but it works just keep staring at the result and you will eventually see you can now integrate
This integral is not obvious. But ask yourself now: what is the derivative of sec x? And of tan x?
still pondering the integral QRA ?
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I understand. Thank you.
I just had to make a substitution for this.
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