Find the perimeter of a triangle with vertices (2,4) (-1,3) and (2, -3).
(show your work on graph paper)
and
solve 3^4x-7=4^2x+3

Question

Find the perimeter of a triangle with vertices (2,4) (-1,3) and (2, -3).
(show your work on graph paper)
and
solve 3^4x-7=4^2x+3

anonymous · Answer

perimer = distance problem

anonymous · Answer

let A be (2,4), B (-1,3), C (2,-3) the three vertices of your triangle.
$$ \begin{align} & |AB| = \sqrt{(3-4)^2+(-1-2)^2} \
&|BC| = \sqrt{(-3-3)^2+(2-(-1))^2}  \
& |AC| = \sqrt{(4-(-3))^2+(2-2)^2} \end{align}$$
do the computation and add the three lenght to get the perimeter.  the general formula for two point $A: (x_a,y_a)\  and\  B:(x_b,y_b) $ is:
$$ |AB| = \sqrt{(y_b-y_a)^2+(x_b-x_a)^2}$$

anonymous · Answer

The second part of your exo has been answered allready here : http://openstudy.com/updates/4f402100e4b0534c53cc0016

anonymous · Answer

@mkone shouldn't you use log here. what's the rules for logs again

anonymous · Answer

please check the link

anonymous · Answer

i checked the link but i dont understand why you can't use logarithm here. why did you use the natural log

anonymous · Answer

You can replace $ln \ by\  log$ it will not change the final result nor the step of the demonstration. $ln$ is just short for me to write