Prove: MNCP is a trapezoid
Oh and the given: is all drawn in the figure
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I'd prove 1 pair of sides are parallel... only property of a trapezoid
Yes I actually thought of that but.. I have no idea how!
is AB perpendicular to MN and CP
Nope
does it bisect angle A
Well, it does not say so but yes <BAC is congruent to <PAB
Oh no! I forgot something..
I think you're right AB is an angle bisector
because
it says that between brackets ( use the angle bisector property ) Do you know it?
I think what meant by that ^ is : AC/AP=CB/BP
the angle bisector property is to do with the ratio of sides. then the ratio BP:BC = AP:AC is MN and AB intersect at X then the property can be applied again XN:XM = AN:AM so the sides are in ratio and you have a congruent angle... so you can prove similarity.... in the triangles.... AMX and ACB the angle A and M are equal because of corresponding angles in similar triangles are equal. and A and M are corresponding angles in parallel lines... so MN is parallel to AB.... hence trapezoid
i think you mixed up the angles... since MN and AB are not parallel (AB intersects MN)
but the idea seems to be correct -- showing that those triangles are similar and so the angles are congruent
Aooh! Nicee :) Thank youuuu :D
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