Question

5^-3*5^7

Answer 1

\[5^{-3}(5^{7})=5^{4}\]

Answer 2

When you multiply and the bases are the same, add the exponents.

Answer 3

that's all you have to do?

Answer 4

Yes. For that problem

Answer 5

wow it's correct!

Answer 6

\[a ^{n} \times a ^{m}=a ^{n+m}\]

Answer 7

w^-9*w^-7 would that be w^-16

Answer 8

Yep. Or you could write it :
\[\frac{1}{w ^{16}}\]

Answer 9

yay! that was correct too...I always have had trouble with math.

Answer 10

Well but now you're older and smarter. You'll probably breeze right through it.

Answer 11

true...ok having more issues again. t^-6 * t= ?

Answer 12

I thougt it would just be t^-6

Answer 13

\[t ^{-6} \times t ^{1}=t ^{-5}\]

Answer 14

oh....

Answer 15

20y^-4 / 4y^-8

Answer 16

5y^4

Answer 17

so 20/4=5.... how did you get to the 4th?

Answer 18

\[\frac{a ^{m}}{a ^{n}}=a ^{m-n}\]

Answer 19

-12a^-2 / 8b^-5 oh, I kind of see what you did there.

Answer 20

\[\frac{-12}{8}=\frac{-3}{2}\]

Answer 21

I get that part....

Answer 22

because you are dividing by four you got that

Answer 23

\[\frac{a ^{-2}}{b ^{-5}}=\frac{b ^{5}}{a ^{2}}\]

Answer 24

ok...so is it supposed to be -3b^5/2a^2?

Answer 25

"/" is a fraction sign by the way

Answer 26

yes. reduced the fraction.

Answer 27

cool! thanks

Answer 28

And yes. The answer you wrote is correct.

Answer 29

so, 5x^-5/y^-10z-1....I got y^10z^1/5x^5, but it's wrong. why?

Answer 30

that would be z^-1, sorry

Answer 31

Because the 5 does not have a negative exponent and it stays where it is.

Answer 32

which 5?

Answer 33

does it stay on the top? or how does end result look like? could the y^10 and z^1 stay on top?

Answer 34

The coefficient

Answer 35

so end result looks like: 5 y^10z^1 / x^5 ?

Answer 36

yes

Answer 37

oh sweet?!

Answer 38

(4m^-6n^-6)^-3

Answer 39

When you raise to a power you multiply the exponents.

Answer 40

So 4^-3m^18n^18

Answer 41

or m*18n^18/64

Answer 42

ok I really don't get this... what is it?

Answer 43

\[(4^1m ^{-6}n ^{-6})^{-3}=4^{-3}m ^{18}n ^{18}=\frac{m ^{18}n ^{18}}{4^{3}}=\frac{m ^{18}n ^{18}}{64}\]

Answer 44

ok....that seems complex for something that looks simple

Answer 45

(m^-1/n^-60^3 does that equal m^-3/n^-18?

Answer 46

\[\frac{m ^{-1}}{(n ^{-60})^{3}}\]

Answer 47

Is that the problem?

Answer 48

no....its (m^-1/n^-6)^3

Answer 49

the m and n is part of the fraction inside the prens. all the stuff in the prens is to the 3rd

Answer 50

\[\frac{m ^{-3}}{n ^{-18}}=\frac{n ^{18}}{m ^{3}}\]

Answer 51

so I see...all that I had left to do was to simplify?

Answer 52

yep

Answer 53

ok I did this one right (I think). (2a^3 / 5b^4)^-2 = 2a^-6 / 5b^-8 = 5b^8 / 2a^6

Answer 54

guess not, online homework said it was wrong :(

Answer 55

\[(\frac{2a ^{3}}{5b ^{4}})^{-2}=\frac{2^{-2}b ^{-6}}{5^{-2}b ^{-8}}\]

Answer 56

Whoops. Make that an a on the top.

Answer 57

ok, how did you get so luck to understand math?

Answer 58

um.....my math homework told me that, that was wrong as well....

Answer 59

\[\frac{5^{2}b ^{8}}{2^{2}a ^{6}}=\frac{25b ^{8}}{4a ^{6}}\]

Answer 60

You are too impatient to wait for the final answer.

Answer 61

oh I see, still needed to be simplified. sorry : (