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Mathematics 10 Online
OpenStudy (anonymous):

I need help with linear algebra

OpenStudy (anonymous):

OpenStudy (amistre64):

we all do, its a shame how they present this stuff

OpenStudy (anonymous):

UMMM question #18 part D

OpenStudy (amistre64):

thats way to blurry for me to read; or i need bifocals ... 50/50 lol

OpenStudy (anonymous):

lol hahaha ok i will resave it give me a sec

OpenStudy (anonymous):

OpenStudy (anonymous):

ok this one is better

OpenStudy (amistre64):

yeah, much better; i feel young again :)

OpenStudy (anonymous):

hahah good

OpenStudy (amistre64):

id d(A,B) the determinate of AB ?

OpenStudy (anonymous):

noo distance

OpenStudy (amistre64):

im gonna have to look that up to be sure .... in the mean time, feel free to browse the gift shop :)

OpenStudy (amistre64):

does this distance function have another name it goes by perchance?

OpenStudy (anonymous):

hmmmm

OpenStudy (amistre64):

i keep getting "distance matrix" that has nothing to do with this problem

OpenStudy (anonymous):

finding distance btwn two vectors

OpenStudy (amistre64):

how did you do it for #17?

OpenStudy (anonymous):

ummm i didnt i only have to do #18

OpenStudy (amistre64):

got it, i think http://tutorial.math.lamar.edu/Classes/LinAlg/InnerProductSpaces.aspx

OpenStudy (amistre64):

d(A,B) = ||A-B||

OpenStudy (amistre64):

A-B 1 -1 -1 1

OpenStudy (anonymous):

ohhhh i cld have given u the formula

OpenStudy (amistre64):

your keeping secrets from me arent you; make him sweat is your plan .... ok

OpenStudy (anonymous):

but teh problem is the condition in the begginning

OpenStudy (anonymous):

how do u work that out

OpenStudy (amistre64):

the inner product? its pretty much self defined if you can read the notation

OpenStudy (anonymous):

cuz i know the answer for #17 part D it 3sqrt(6)

OpenStudy (amistre64):

\(a_{rc}\) tells us matrix A, row and column entry

OpenStudy (anonymous):

amistre i gtg but i will be back to check the answer

OpenStudy (anonymous):

Thanks :D

OpenStudy (amistre64):

which in this case is 0 2*1.0 + 0.1 + 1.0 + 2*0.1 = 0

OpenStudy (amistre64):

im gonna work and see if i can get that for #17 to see if im doing it right

OpenStudy (amistre64):

got it ... maybe :) #17 -1 3 0 -2 4 -2 1 1 d(A,B) = ||A-B|| -1 5 3 -3 ^2 and add the results 1+25+9+9 = 54 ; now sqrt them. sqrt(54) = sqrt(9*6) = 3sqrt(6)

OpenStudy (amistre64):

#18 would then be the same process ... A B 10 01 01 10 A-B = 1 -1 -1 1 ^2 that parts, add and sqrt 1+1+1+1 = 4; sqrt(4) = 2

OpenStudy (anonymous):

Thanks Amistre. I was doing the same thing but somehow got my arithmetic wrong. Thanks again @amistre64

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