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Evaluate the derivative using logarithmic differentiation if y = x(x + 5)^3/(6x − 1)^2
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Lny = Ln[x(x + 5)^3/(6x − 1)^2] Lny = Lnx + Ln(x+5)^3 - Ln(6x-1)^2
Lny = Lnx + 3 Ln(x+5) - 2 Ln(6x-1) (1/y)y' = (1/x) + 3/(x+5) - 2/(6x-1)
y' = y*[(1/x) + 3/(x+5) - 2/(6x-1)]
and now just replace y with the equation taht u had for y
the original one at the very top?
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Yes \[ y = {x(x + 5)^3 \over (6x − 1)^2}\]
its saying its wrong idk y
so its -12?
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