At noon, ship A is 20 miles due west of ship B. Ship A is sailing west at 24 mph and ship B is sailing north at 23 mph. How fast (in mph) is the distance between the ships changing at 3 PM?
sighh.. Jinnie lol nobody seems to want to do this.. i was hoping someone would lol
lol yeah. i really hope so too since this is due tomorrow lol
i found a similar problem...lets try this user solution At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 21 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) this is a cal problem. math - Damon, Saturday, July 9, 2011 at 9:30pm after 4 hours x = - 30 - 21*4 = - 114 y = 15*4 = 60 dx/dt = -21 dy/dt = 15 D at 4 hr = sqrt(114^2+60^2) = 129 D^2 = x^2 + y^2 2 D dD/dt = 2 x dx/dt + 2 y dy/dt 129 dD/dt = -114(-21) + 60(15) dD/dt = 25.5 knots
so far i got x=-132 y=69
dx/dt= -24 dy/dt=23
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