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A square is inscribed in a circle. If the radius of the circle is increasing at a rate of 3 cm/min, find how fast the area of the square is increasing when the radius is 10 cm.
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OK, here goes:
r=d/2 s=d/sqrt(2) a=s^2=2r^2 da/dr = 4r da/dt = da/dr dr/dt = 4r dr/dt = 4r (3 cm/min) = 12r cm/min at r=10cm this is da/dt = 120 cm^2/min
thank you =)
You're welcome. Good problem. Points for your math teacher.
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