Question

please prove. :D step by step preferably.
cotx/(cscx+1) = secx-tanx

Answer 1

never mind i got it!!! :)

Answer 2

In case of other people who wants to know the answer,
(cotx)/(cscx+1)=secx-tanx

(cotx(cscx-1))/(csc^(2)x-1)

(cscx-1)/(cotx)

cscx/cotx-1/cotx

(cscx)/((cosx)/(sinx))-(1)/(cotx)

(cscxsinx)/(cosx)-(1)/(cotx)

1/(cosx)-1/(cotx)

1/(cosx)-1/((cosx)/(sinx))

1/(cosx)-(sinx)/(cosx)

sec(x)-(sinx)/(cosx)

sec(x)-tanx