Question

Two speakers are separated by a distance of 3.6m. A point P is placed at 6.9m from one of the speakers so that they form a right triangle. If the speed of sound in this situation is 338m/s and the speakers are in phase, what is the lowest frequency for which the intensity at P is:
a) a maximum
b) a minimum

Answer 1

path difference is 0.88 m

Answer 2

phase difference = (2pi x path diff)/lambda

Answer 3

lambda = v/f
for max phase diff = 0, for min phase diff = pi

Answer 4

got it??

Answer 5

then wouldnt it be 0, and sry i didnt get a notifciation for someone replying