Question

Find the work done in breaking a water drop of radius 1 mm into 1000 drops. Given the surface tension of water is 72 × 10-3 N/m?

Answer 1

first find radius of each of 1000 drops
as
volume of 1 drop(first)=volume of 1000 single drops
4/3pi*Rcube=4/3*pi*rcube*1000
work is done by surface energy=surface tension*increse in surface area

surface area of 1000 new drops is definitely greater than surface area of a single water drop
surface area=4*pi*rsquare