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Mathematics 18 Online
OpenStudy (anonymous):

Hi, is it possible to solve this equation: u (∂lnγ/∂x) = (-1/p) (∂p/∂x)

OpenStudy (2bornot2b):

Ghostdog, did you know you can chat with users in the mathematics group, thus get help from experts?

OpenStudy (anonymous):

Nope, first time. Where do I go?

OpenStudy (2bornot2b):

Just the green box below

OpenStudy (anonymous):

Thanks

OpenStudy (2bornot2b):

I am actually chatting with you right now

OpenStudy (bahrom7893):

Okay, what are we supposed to do?

OpenStudy (bahrom7893):

hmm partial derivatives..

OpenStudy (bahrom7893):

nenand, save the day? plz?

OpenStudy (nenadmatematika):

well, what is p? is it a function, constant?

OpenStudy (bahrom7893):

it's a variable.. i think

OpenStudy (anonymous):

What I'm trying to do is to calculate u. p is a variable.

OpenStudy (bahrom7893):

just divide both sides by d(lny)/dx then

OpenStudy (anonymous):

This is the formula for calculating horizontal wind speed (u). p is atmospheric pressure and y is the mixing ratio.

OpenStudy (nenadmatematika):

ok...If u is the function which argument is partial derivative of lny, then that derivative of lny is 0 so you have u(0)

OpenStudy (nenadmatematika):

if y is not y(x) of course

OpenStudy (anonymous):

I am not too sure. I got it from this article: http://www.bioticregulation.ru/common/pdf/ijw10.pdf; see equation 17

OpenStudy (anonymous):

I have p for two points on the x axis. y is the mixing ratio depending on x, it is not the y-axis

OpenStudy (anonymous):

So, imagine we a point x1 and x2, that have p1 and p2 of 1050mbar and 1000mbar, respectively. y1 and y2 are about 0.05 and 0.04 respectively. What I want to calculate is u

OpenStudy (anonymous):

ie the wind speed between these two points

OpenStudy (nenadmatematika):

hmmm...there's a lot of material above this equation....a lot of physics....not so sure about this....maybe if u(0)=0, in that case you will get basic equation where the only solution is that that partial derivative of p is 0....but, just assuming, because I don't have basics of physics to this with understanding...sorry :(

OpenStudy (nenadmatematika):

I think that the best way is to post this in some physics group...

OpenStudy (anonymous):

I will do this. thanks for your time anyways

OpenStudy (anonymous):

if u is 0 then the pressure p at point x1 and x2 are the same

OpenStudy (amistre64):

not sure but: u (∂lnγ/∂x) = (-1/p) (∂p/∂x) ^^^ this = 0 since lny is a constant with respect to x or is the notation misleading?

OpenStudy (amistre64):

yeah, theres alot of stuff going on way before this to sort out ...

OpenStudy (2bornot2b):

Thanks a lot amistre!

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