Geometry: If segment JK measures 12 feet and segment JM is congruent to segment KM, what is the approximate length of segment JM? http://i44.tinypic.com/wpgyq.png I disagree with the answer key and trying to make sure I'm not going crazy.
JKL is an isosceles triangle with congruent sides JK and KL JK = 12 ft, so KL = 12 ft The measure of JM would be 1/2 of JL, because KM is perpendicular to JL (given) and KM extends from the vertex angle of the isosceles triangle JKL to the base, making it a perpendicular bisector to JL JM = 1/2 (JL) We can find the length of JL by Pythagorean Theorem (a^2 + b^2 = c^2 JK^2 + KL^2 = JL^2 12^2 + 12^2 = JL^2 288 = JL^2 12sqrt(2) = JL JM = 1/2 (12 sqrt(2)) JM = 6 sqrt(2) ~ 8.5 (8.48528...)
by pythagoras 12^2 = 2 JM^2 (since JM = KM) jm = sqrt72 = 8.5 approx
that works too, and is a lot less work lol
thank you both
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