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lim x-->-2^- (x-3)|x+2|/(x+2)
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|x+2|=-(x+2) since x<-2
\[\lim_{x \rightarrow -2^-}-\frac{(x-3)(x+2)}{x+2}=\lim_{x \rightarrow -2^-}-(x-3)=-(-2-3)=-(-5)=5\]
should i follow the same procedure in case of lim x--> 2+^
is that x->-2^+?
yes
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that would mean |x+2|=x+2 since x>-2
\[\lim_{x \rightarrow -2^+}\frac{(x-3)(x+2)}{x+2}=\lim_{x \rightarrow -2^+}(x-3)=-2-3=-5\]
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