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what is logbasex27=-3 explain please
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\[\log_{x} 27=-3\]
\[x^{-3}=27\] is a start
We have \[ \log_{x} 27=-3\] we know that \[ \log_{a} b= c=> b=a^c\] so here we have \[ \log_{x} 27=-3\] \[=> 27= x^{-3}\] or \[ 27=(\frac{1}{x})^3\] We know that3^3=27 so \[\frac{1}{x}=3\] we get \[x=\frac{1}{3}\]
i read the question wrong..
\[x^{-3}=3^3\] \[x^{-3}=(\frac{1}{3})^{-3}\]
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oh i see now thanks for showing the steps
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