Question

How many different three digit numbers greater than 240 can be formed by using three different digits from the set (1, 2, 3, 4)?

Answer 1

2 in the 2 hundreds. 6 in the 3 hundreds. 6 in the 4 hundreds.

So, 14 I think.

Answer 2

241
243
312
314
321
324
341
342
412
413
421
423
431
432

Answer 3

Assuming no repetitions allowed.

Answer 4

First digit can either be 2 , 3or 4
When it's 2
the second place has to be 4
the third place can be occupied by 1 or 3
\[1\times 1\times 2=2\]
When the first digit is eithere 3 or 4
We choose the first digit in 2 ways
the other two digits from three no.s can be chosen as \[3\times2=6\]
Total no.s =\[2\times 6=12\]
Total=12+2=14

Answer 5

I'm confused, some say 14, and you say 12 *_*

Answer 6

Maybe I was too "excited." Let me rethink. Go ahead and post your next question. I'll catch up.

Answer 7

Saki it's 14 only

Answer 8

Directrix missed the "two" numbers possible in the two hundreds, and never added those two to his/her 12. That is the difference.

Right answer is 14 = 12 + 2