Question

Use quadratic formula to solve?
2x^2+5x-6=0

Answer 1

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
a = 2, b = 5, c = -6

Answer 2

\[So...-5\pm \sqrt{(5)^{2}}-4(2)(-6)\]

Answer 3

/2(2)

Answer 4

yes, although the square root should also include the - 4(2)(-6).

Answer 5

So, \[-5\sqrt{25-48}/4\]

Answer 6

-5 +- sqrt(25 - 4(2)(-6) )
----------------------
4

try rechecking that - 4(2)(-6).. There are two negatives being multiplied together (-4, -6) so you should be getting a positive.

Answer 7

Dang it...yeah, so -5*-73/4

Answer 8

Is it 25 + 48?

Answer 9

yes

im not sure why you are multiplying the -5 to the root, it should be a plus-minus sign

Answer 10

That was a typo, I meant to put +-

Answer 11

ah, okay. but yes, you would be correct with 25 + 48.

Answer 12

So do you get x = -3.2679?

Answer 13

Wait...just a sec

Answer 14

-2.86399

Answer 15

i got...

-5 + sqrt(73) -5 - sqrt(73)
-------------, -------------
4 4

Answer 16

Oh, just leave it like that?

Answer 17

yeah, it doesn't ask for approximations, so it would be sufficient to keep it in that form

Answer 18

OMG...thank you. There's so many steps to mess up on. Thanks for your time

Answer 19

Yeah, the tricky part (aside from memorizing the formula itself) is usually just getting all the arithmetic correct. :P