Question

prove that : cos64 + sin 64 * tan32 = 1

Answer 1

cos64 = cos[2(32)] = cos^2 (32) - sin^2 (32)
sin 64 = sin[2(32)] = 2sin32cos32
tan32 = sin32 / cos32

cos64 + sin 64 * tan32 =
cos^2 (32) - sin^2 (32) + 2sin32cos32* sin32 / cos32
= cos^2 (32) - sin^2 (32) + 2sin^2 (32)
=cos^2 (32) + sin^2 (32)
=1

Answer 2

thank you so much dude :) i really appreciate it

Answer 3

my pleasure XD

Answer 4

\[\tan ^2x =( \cos (180-x)\sin(x-90)-1)\[\div\]tan^2(180+x)\sin(90+x)\cos(-x)\]